Limit Fungsi Trigonometri - Latihan Soal Tambahan

Tentukan nilai dari limit fungsi trigonometric berikut!

\(\begin{align}\mathrm{\lim_{x→0}\frac{tan\,x}{x}}\end{align}=\,...\)

\(\begin{align}\mathrm{\lim_{x→0}\frac{x}{tan\,x}}\end{align}=\,...\)

\(\begin{align}\mathrm{\lim_{x→0}\frac{sin\,2x}{3x}}\end{align}=\,...\)

\(\begin{align}\mathrm{\lim_{x→0}\frac{4x}{sin\,5x}}\end{align}=\,...\)

\(\begin{align}\mathrm{\lim_{x→0}\frac{tan\,7x}{9x}}\end{align}=\,...\)

\(\begin{align}\mathrm{\lim_{x→0}\frac{6x}{tan\,8x}}\end{align}=\,...\)

\(\begin{align}\mathrm{\lim_{x→0}\frac{sin\,9x}{sin\,10x}}\end{align}=\,...\)

\(\begin{align}\mathrm{\lim_{x→0}\frac{tan\,15\,x}{tan\,25\,x}}\end{align}=\,...\)

\(\begin{align}\mathrm{\lim_{x→0}\frac{sin\,5x}{tan\,35\,x}=\,...}\end{align}\)

\(\begin{align}\mathrm{\lim_{x→0}\frac{tan\,100\,x}{sin\,75\,x}=\,...}\end{align}\)

Tentukan nilai dari limit fungsi trigonometrik berikut!

\(\begin{align}\mathrm{\lim_{x→0}\frac{sin\,4x+tan\,3x-sin\,5x}{2x}=\,...}\end{align}\)

\(\begin{align}\mathrm{\lim_{x→0}\frac{cot\,5x}{cot\,10x}=\,...}\end{align}\)

\(\begin{align}\mathrm{\lim_{x→0}\frac{tan^{3}5x}{(10x)^{2}sin\left (\frac{1}{2}x\right )}=\,...}\end{align}\)

\(\begin{align}\mathrm{\lim_{x→\frac{\pi}{2}}\frac{sin\left (x-\frac{\pi}{2}\right )}{\left (x-\frac{\pi}{2}\right )(3x)}=\,...}\end{align}\)

\(\begin{align}\mathrm{\lim_{x→1}\frac{(3x+1)sin(x-1)}{x^{2}+2x-3}=\,...}\end{align}\)

\(\begin{align}\mathrm{\lim_{x→0}\frac{sin^{2}4x}{x^{2}}=\,...}\end{align}\)

\(\begin{align}\mathrm{\lim_{x→0}\frac{sin\,4x+tan\,3x}{x}=\,...}\end{align}\)

\(\begin{align}\mathrm{\lim_{x→0}\frac{sin^{3}2x}{tan^{3}\frac{1}{2}x}=\,...}\end{align}\)

\(\begin{align}\mathrm{\lim_{x→0}\frac{x-2\,sin\,x}{tan\,x}=\,...}\end{align}\)

\(\begin{align}\mathrm{\lim_{x→0}\frac{tan\,x-x}{sin\,x+x}=\,...}\end{align}\)

Tentukan nilai dari limit fungsi trigonometrik berikut!

\(\begin{align}\mathrm{\lim_{x→0}\frac{1-cos\,2x}{9x^{2}}=\,...}\end{align}\)

\(\begin{align}\mathrm{\lim_{x→0}\frac{cos\,x-1}{tan^{2}2x}=\,...}\end{align}\)

\(\begin{align}\mathrm{\lim_{x→0}\frac{tan\,x-sin\,x}{x\,cos\,x}=\,...}\end{align}\)

\(\begin{align}\mathrm{\lim_{x→\pi}\frac{1+cos\,x}{(x-\pi)^2}=\,...}\end{align}\)

\(\begin{align}\mathrm{\lim_{x→0}\frac{1-cos\,x}{1-cos\,2x}=\,...}\end{align}\)

\(\begin{align}\mathrm{\lim_{x→1}\frac{1-cos^2(x-1)}{4x^{2}-8x+4}=\,...}\end{align}\)

\(\begin{align}\mathrm{\lim_{x→-2}\frac{2-2\,cos(x+2)}{x^{2}+4x+4}=\,...}\end{align}\)

\(\begin{align}\mathrm{\lim_{x→0}\frac{tan^{2}3x}{1-cos\,2x}=\,...}\end{align}\)

\(\begin{align}\mathrm{\lim_{x→0}\frac{x^3}{tan\,x-sin\,x}=\,...}\end{align}\)

\(\begin{align}\mathrm{\lim_{x→0}\frac{tan\,3x-tan\,3x\,cos\,2x}{4x^{3}}=\,...}\end{align}\)

Tentukan limit fugsi trigonometrik berikut!

\(\begin{align}\mathrm{\lim_{x→0}\frac{sin\,x+tan\,2x}{3x-sin\,4x}=\,...}\end{align}\)

\(\begin{align}\mathrm{\lim_{x→0}\frac{(x^{2}-1)\,sin\,6x}{x^{3}+3x^{2}+2x}=\,...}\end{align}\)

\(\begin{align}\mathrm{\lim_{x→a}\frac{x-a}{(x-a)-2x+2a}=\,...}\end{align}\)

\(\begin{align}\mathrm{\lim_{x→2a}\frac{3x-6a}{tan(x-2a)+3x-6a}=\,...}\end{align}\)

\(\begin{align}\mathrm{\lim_{x→2}\frac{(x^{2}-5x+6)\,sin(x-2)}{(x^{2}-x-2)^2}=\,...}\end{align}\)

\(\begin{align}\mathrm{\lim_{x→0}\frac{x\,tan\,x}{1-cos\,3x}=\,...}\end{align}\)

\(\begin{align}\mathrm{\lim_{x→0}\frac{(1-cos\,2x)\,sin\,5x}{x^{2}sin\,3x}=\,...}\end{align}\)

\(\begin{align}\mathrm{\lim_{x→0}\frac{1\sqrt{cos\,x}}{x^2}=\,...}\end{align}\)

\(\begin{align}\mathrm{\lim_{x→0}\frac{\sqrt{1+cos\,2x}-\sqrt{2}}{sin^{2}x}=\,...}\end{align}\)

\(\begin{align}\mathrm{\lim_{x→0}\frac{\frac{\pi}{3}-\left (x+\frac{\pi}{3}\right )\,cos\,x}{sin\,x}=\,...}\end{align}\)